In mathematics, the unitary group of degree n, denoted U( n), is the group of Unitary matrix, with the group operation of matrix multiplication. The unitary group is a subgroup of the general linear group , and it has as a subgroup the special unitary group, consisting of those unitary matrices with determinant 1.
In the simple case , the group U(1) corresponds to the circle group, isomorphic to the set of all that have absolute value 1, under multiplication. All the unitary groups contain copies of this group.
The unitary group U( n) is a real number Lie group of dimension n2. The Lie algebra of U( n) consists of skew-Hermitian matrices, with the Lie algebra given by the commutator.
The general unitary group, also called the group of unitary similitudes, consists of all matrices A such that A∗ A is a nonzero multiple of the identity matrix, and is just the product of the unitary group with the group of all positive multiples of the identity matrix.
Unitary groups may also be defined over fields other than the complex numbers. The hyperorthogonal group is an archaic name for the unitary group, especially over .
The kernel of this homomorphism is the set of unitary matrices with determinant 1. This subgroup is called the special unitary group, denoted SU( n). We then have a short exact sequence of Lie groups:
The above map U( n) to U(1) has a section: we can view U(1) as the subgroup of U( n) that are diagonal with eiθ in the upper left corner and 1 on the rest of the diagonal. Therefore U( n) is a semidirect product of U(1) with SU( n).
The unitary group U( n) is not abelian group for . The center of U( n) is the set of scalar matrices λI with ; this follows from Schur's lemma. The center is then isomorphic to U(1). Since the center of U( n) is a 1-dimensional abelian normal subgroup of U( n), the unitary group is not semisimple, but it is Reductive group.
As a topological space, U( n) is both compact space and connected space. To show that U( n) is connected, recall that any unitary matrix A can be diagonalized by another unitary matrix S. Any diagonal unitary matrix must have complex numbers of absolute value 1 on the main diagonal. We can therefore write
A path in U( n) from the identity to A is then given by
The unitary group is not simply connected; the fundamental group of U( n) is infinite cyclic for all n: Proposition 13.11
To see this, note that the above splitting of U( n) as a semidirect product of SU( n) and U(1) induces a topological product structure on U( n), so that
Now the first unitary group U(1) is topologically a circle, which is well known to have a fundamental group isomorphic to Z, whereas SU( n) is simply connected. Proposition 13.11
The determinant map induces an isomorphism of fundamental groups, with the splitting inducing the inverse.
The Weyl group of U( n) is the symmetric group S n, acting on the diagonal torus by permuting the entries:
Thus a unitary structure can be seen as an orthogonal structure, a complex structure, and a symplectic structure, which are required to be compatible (meaning that one uses the same J in the complex structure and the symplectic form, and that this J is orthogonal; writing all the groups as matrix groups fixes a J (which is orthogonal) and ensures compatibility).
In fact, it is the intersection of any two of these three; thus a compatible orthogonal and complex structure induce a symplectic structure, and so forth.
At the level of equations, this can be seen as follows:
\text{Symplectic} &
A^\mathsf{T}JA = J \\
\hline
\text{Complex} &
A^{-1}JA = J \\
\hline
\text{Orthogonal} &
A^\mathsf{T} = A^{-1}
\end{array}
Any two of these equations implies the third.
At the level of forms, this can be seen by decomposing a Hermitian form into its real and imaginary parts: the real part is symmetric (orthogonal), and the imaginary part is skew-symmetric (symplectic)—and these are related by the complex structure (which is the compatibility). On an almost Kähler manifold, one can write this decomposition as , where h is the Hermitian form, g is the Riemannian metric, i is the almost complex structure, and ω is the almost symplectic structure.
From the point of view of , this can partly be explained as follows: O(2 n) is the maximal compact subgroup of , and U( n) is the maximal compact subgroup of both and Sp(2 n). Thus the intersection or is the maximal compact subgroup of both of these, so U( n). From this perspective, what is unexpected is the intersection .
The above is for the classical unitary group (over the complex numbers) – for unitary groups over finite fields, one similarly obtains special unitary and projective unitary groups, but in general .
This can be generalized in a number of ways:
Given a Hermitian form Ψ on a complex vector space V, the unitary group U(Ψ) is the group of transforms that preserve the form: the transform M such that for all . In terms of matrices, representing the form by a matrix denoted Φ, this says that .
Just as for symmetric forms over the reals, Hermitian forms are determined by signature, and are all unitarily congruent to a diagonal form with p entries of 1 on the diagonal and q entries of −1. The non-degenerate assumption is equivalent to . In a standard basis, this is represented as a quadratic form as:
and as a symmetric form as:
The resulting group is denoted .
Thus one can define a (unique) unitary group of dimension n for the extension F q2/ F q, denoted either as or depending on the author. The subgroup of the unitary group consisting of matrices of determinant 1 is called the special unitary group and denoted or . For convenience, this article will use the convention. The center of has order and consists of the scalar matrices that are unitary, that is those matrices cIV with . The center of the special unitary group has order and consists of those unitary scalars which also have order dividing n. The quotient of the unitary group by its center is called the projective unitary group, , and the quotient of the special unitary group by its center is the projective special unitary group . In most cases ( and }), is a perfect group and is a finite simple group, .
First, there is a unique k-automorphism of K which is an involution and fixes exactly k ( if and only if ).Milne, Algebraic Groups and Arithmetic Groups, p. 103 This generalizes complex conjugation and the conjugation of degree 2 finite field extensions, and allows one to define Hermitian forms and unitary groups as above.
For the field extension C/ R and the standard (positive definite) Hermitian form, these yield an algebraic group with real and complex points given by:
\operatorname{U}(n, \mathbf{C}/\mathbf{R})(\mathbf{R}) &= \operatorname{U}(n) \\
\operatorname{U}(n, \mathbf{C}/\mathbf{R})(\mathbf{C}) &= \operatorname{GL}(n, \mathbf{C}).
\end{align}
In fact, the unitary group is a linear algebraic group.
To define it, one has to define quadratic modules first:
Let R be a ring with anti-automorphism J, such that for all r in R and . Define
\Lambda_\text{min} &:= \left\{r \in R \ : \ r - r^J\varepsilon\right\}, \\
\Lambda_\text{max} &:= \left\{r \in R \ : \ r^J\varepsilon = -r\right\}.
\end{align}
Let be an additive subgroup of R, then Λ is called form parameter if and . A pair such that R is a ring and Λ a form parameter is called form ring.
Let M be an R-module and f a J-sesquilinear form on M (i.e., for any and ). Define and , then f is said to define the Λ-quadratic form on M. A quadratic module over is a triple such that M is an R-module and is a Λ-quadratic form.
To any quadratic module defined by a J-sesquilinear form f on M over a form ring one can associate the unitary group
The special case where , with J any non-trivial involution (i.e., and gives back the "classical" unitary group (as an algebraic group).
C_1 &= \left(u^2 + v^2\right) + \left(w^2 + x^2\right) + \left(y^2 + z^2\right) + \ldots \\
C_2 &= \left(uv - vu\right) + \left(wx - xw\right) + \left(yz - zy\right) + \ldots
\end{align}
These are easily seen to be the real and imaginary parts of the complex form . The two invariants separately are invariants of O(2 n) and Sp(2 n). Combined they make the invariants of U( n) which is a subgroup of both these groups. The variables must be non-commutative in these invariants otherwise the second polynomial is identically zero.
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